![In figure, G is the point of concurrence of medians of DEF. Take point H on ray DG such that DG = GH, then prove that GEHF is a parallelogram. In figure, G is the point of concurrence of medians of DEF. Take point H on ray DG such that DG = GH, then prove that GEHF is a parallelogram.](https://haygot.s3.amazonaws.com/questions/1109109_1052033_ans_2bf1d1ca077843f7adca264ca010b832.jpg)
In figure, G is the point of concurrence of medians of DEF. Take point H on ray DG such that DG = GH, then prove that GEHF is a parallelogram.
![Modern geometry . be two equicross ranges, and ifA A, BB, CC be concurrent, then dd must pass throughthe point of concurrence.. fig. 76. Let O be the point of concurrence of Modern geometry . be two equicross ranges, and ifA A, BB, CC be concurrent, then dd must pass throughthe point of concurrence.. fig. 76. Let O be the point of concurrence of](https://c8.alamy.com/comp/2AM4MGD/modern-geometry-be-two-equicross-ranges-and-ifa-a-bb-cc-be-concurrent-then-dd-must-pass-throughthe-point-of-concurrence-fig-76-let-o-be-the-point-of-concurrence-of-aa-bb-ccif-dd-does-not-pass-through-o-let-od-cut-ab-in-dthen-ab-cd-=-ab-cd-=-ab-cd-a-d-b-ac-db-caf-cb-ad-d-db-aa-d-coincides-with-d-dd-passes-through-o-cross-batio-131-note-this-theorem-and-theorem-51-could-be-stated-astheorem-and-converse-it-must-be-carefully-noted-that-it-isgenerally-not-true-that-if-abcd-=-abcd-then-aa-bb-ccdd-are-concurrent-ex-535-examine-2AM4MGD.jpg)
Modern geometry . be two equicross ranges, and ifA A, BB, CC be concurrent, then dd must pass throughthe point of concurrence.. fig. 76. Let O be the point of concurrence of
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CONVERSE. Comment la marque a toujours été… | by Candice Boulot | Marketing, Marques & Innovation — Bordeaux | Medium
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CONVERSE. Comment la marque a toujours été… | by Candice Boulot | Marketing, Marques & Innovation — Bordeaux | Medium
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